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The graphics facilities available to us are worse than pathetic so you will have to do with a descriptive answer.
Plot the graph of 2x -4y = 4 (I am assuming that there is a "=" sign there). To do this, cover up "-4y". This leave 2x = 4 and, on dividing by 2, x = 2. Thus x=2, y=0 or (2, 0) is one point on the graph. Next cover up "2x", which leaves -4y = 4 so that y = -1 and so (0, -1) is another point on the graph. Mark these two points on a coordinate plane, join them together with a straight line and extend the line in both directions.
Repeat for the second equation. The two lines will intersect and th coordinates of their point of intersection is the solution.
Further Information:
If you mean: 2x-4y = 4 and 3x-y = 4
Coordinates of 1st line: (2, 0) and (0, -1)
Coordinates of 2nd line: (4/3x, 0) and (0, -4)
Graph the two lines on the Cartesian plane and where they intersect are the solutions to the equations which works out as x = 1.2 and y = -0.4
The first step is to include the - or + values for the given terms
-2x-10y-12+3xy=4Put all x's to the other side and the ones with y's on the other:-10y+3xy=4+2x+12-10y+3xy=16+2xNow you factor a y from the side with the y's:y(-10+3x)=16+2xDivide both sides by (-10+3x):y=(16+2x)/(-10+3x)
2x+3xy-4y=10to solve for yyour objective will be to get y by itself on one side of the equal signyou first subtract 2x to get the terms with y variables on one side3xy-4y=10-2xthen undistribute the y from the two terms to get one yy(3x-4)=10-2xnow divide 3x-4y=(10-2x)/(3x-4)theres your answer
3xy2z
5x + 8xy + 10x + 3xy = 15x + 11xycombine like terms (the x's and the xy's)
3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20
3xy - 3xy = 0
The first step is to include the - or + values for the given terms
18x3y5 + 9xy3 - 3xy = 3xy(6x2y4 + 3y2 - 1)
1,3,x,y,3x,3y,xy,3xy
3xy
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
-2x-10y-12+3xy=4Put all x's to the other side and the ones with y's on the other:-10y+3xy=4+2x+12-10y+3xy=16+2xNow you factor a y from the side with the y's:y(-10+3x)=16+2xDivide both sides by (-10+3x):y=(16+2x)/(-10+3x)
3xy and 2xy. You can see that 3xy and 2xy have something in common with each other. They both have xy and the end of them. Hope this helped.
3xy + 3y2 = 3y (x + y)
4
2x+3xy-4y=10to solve for yyour objective will be to get y by itself on one side of the equal signyou first subtract 2x to get the terms with y variables on one side3xy-4y=10-2xthen undistribute the y from the two terms to get one yy(3x-4)=10-2xnow divide 3x-4y=(10-2x)/(3x-4)theres your answer