Q: How do you solve 2x plus 5 -5?

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X should be zeroas:X + 5 = 2X + 5so, 2X - X = 0 or X = 0

X=6

Solve for y.2x+y=5*subtract 2x from both sides*2x+y-2x=5-2xy=-2x+5 / y=5-2x

3x+5=4-2x+6 5x=4-1 5x=3 x=3/5

If you mean 2(x+5) + (3*5) then it can be simplified to: 2x+25

Related questions

X should be zeroas:X + 5 = 2X + 5so, 2X - X = 0 or X = 0

If: x+1+2x = 1x+5 Then: x = 2

X=6

Solve for y.2x+y=5*subtract 2x from both sides*2x+y-2x=5-2xy=-2x+5 / y=5-2x

Y=0.5 and X=1

3x+5=4-2x+6 5x=4-1 5x=3 x=3/5

If you mean 2(x+5) + (3*5) then it can be simplified to: 2x+25

6x-8+2x-5 = 7-2x 6x+2x+2x = 7+8+5 10x = 20 x = 20/10 x = 2

2x+a=p 2x=p-a x=.5p-.5a

3x-2 = 2x+3 3x-2x = 3+2 x = 5

x = 0 right 2x + 5 = 5 which makes 5 = 5 +2x subtract 5 from each side -5 -5 ---------- 0=0 + 2x 0= 2x substitue x 0 = 2 X 0 solve

To solve this equation we have to isolate and solve for x. So: 2x-6= x+5 +6 +6 2x = x+11 -x -x x = 11 So x=11.