2x2 = x+1 => 2x2-x-1= 0
Divide all terms by 2:
x2-1/2x-1/2 = 0
Completing the square:
(x-1/4)2-1/2 = 0
(x-1/4)2-1/2-1/16 = 0
(x-1/4)2-9/16 = 0
(x-1/4)2 = 9/16
Square root both sides:
x-1/4 = -/+ 3/4
x = 1/4 -/+ 3/4
x = -1/2 and x = 1
It cannot be solved because the discriminant of the quadratic equation is less than zero
If x squared -10 = 0 then x = the square root of 10
Square root both sides and then x = 4
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
Yes and x = 2+square root of 6 or x = 2-square root of 6
It cannot be solved because the discriminant of the quadratic equation is less than zero
i want to solve few questions of completing square method can u give me some questions on it
If x squared -10 = 0 then x = the square root of 10
Square root both sides and then x = 4
If x squared equals n, then x is the square root of n.
Solve this problem -x squared -40x- 80 =0
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
5.
x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i
Yes and x = 2+square root of 6 or x = 2-square root of 6
This quadratic equation has no solutions because the discriminant is less than zero.
If r-squared = theta then r = ±sqrt(theta)