The Quadratic Formula gives the value of x in equations of the form ax2 + bx + c.
In this instance a = 4, b = 11 and c = -21.
((-b +/-(sqrt(b2 - 4ac))/2a
= (-11 +/- sqrt (121 + 336))/ 8
= (-11 +/- 21.4)/8
x = 1.3 or 4.05
If x squared -10 = 0 then x = the square root of 10
You have to put your heart into it!
x = 25 / 3squared + 5
Without an "equals" word or sign somewhere, there is nothing to solve.You only have an expression, not an equation.
-5x2 = -75 x2 = 25 x = ±sqrt( 25 ) x = ±___
Solve this problem -x squared -40x- 80 =0
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
X=1
If x squared -10 = 0 then x = the square root of 10
First you must square the 6 which the answer is 36. Then you subtract 36 from 8 and the answer is negative 28. Finally you solve negative 28 minus 28 (-28-28) which equals negative 56 (-56).
You have to put your heart into it!
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a^(2) - b^(2) + ac - bc Factor ( a - b)( a + b) + c(a - b) Factor further (a - b)(a + b + c) Done!!!!!
x = 25 / 3squared + 5
Without an "equals" word or sign somewhere, there is nothing to solve.You only have an expression, not an equation.
-5x2 = -75 x2 = 25 x = ±sqrt( 25 ) x = ±___
It can be solved by using the quadratic equation formula.