Q: How do you solve 5x2 equals 11?

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5x2 = 3 then x2 = 3/5 so that x = sqrt(3/5) = Â± 0.7746

1) 5x2-55=90 +55 +55 2) 10x=145 /10 /10 x=14.5

5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3

X= (3/5 , -2)

5x2=8x Divide with x on both sides5x= 8 Solve xx=8/5

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5x2 = 3 then x2 = 3/5 so that x = sqrt(3/5) = Â± 0.7746

1) 5x2-55=90 +55 +55 2) 10x=145 /10 /10 x=14.5

5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3

X= (3/5 , -2)

5x2=8x Divide with x on both sides5x= 8 Solve xx=8/5

-5x2 = -75 x2 = 25 x = ±sqrt( 25 ) x = ±___

x2 • (5x2 + x + 8)

5x2-8x-4

5x2-2x = 0 x(5x-2) = 0 Therefore: x = 0 or x = 2/5

Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.

h = +11 and/or -11

5x2=10...take 5 two times..5+5=10