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You can't do it with 9 different integers. Either you repeat integers or you use fractions.

Repeating integers gives the trivial solution 4-4-4; 4-4-4; 4-4-4 so we head into fraction country.

Top row: 1.6 - 7.2 - 3.2; middle row: 5.6 - 4 - 2.4; bottom row: 4.8 - 0.8 - 6.4

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Q: How do you solve a 3x3 magic square with the sum of 12?
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How do you solve a 3x3 magic square with the sum of 6?

A normal 3x3 magic square has a sum of 15. So you subtract 3 from each number in the square.


In a 3x3 magic square what is the relationship between the center number and the sum?

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How do you solve this 3x3 magic square problem with decimals?

To solve a 3x3 magic square with decimals, you need to ensure that the sum of numbers in each row, column, and diagonal is equal. Start by placing the decimal numbers in a way that each row, column, and diagonal sums up to the same value. Adjust the numbers carefully to achieve a valid solution.


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A 3x3 magic square means that each row, each column, and both diagonals all have the same sum.


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3*3=9 9 is the answer.


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There are 9 numbers. Assuming the question refers to a 3x3 "magic" square, the answer is no. The sum of all nine numbers is 36 so each of the 3 rows must sum to 12.


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