2x-y=14, x=0
First, substitute 0 in place of x.
(2x0)-y=14
Multiply 2 times 0.
0-y=14
That gives you...
-y=14
Because we are solving for y, and y must be positive, divide each side by -1.
-y/-1=14/-1
And, our result...
y=-14
2sinx+1 equals 0
For y - 2y - 3y equals 0, y equals 0.
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
many solutions
It's an hyperbola equation.
2sinx+1 equals 0
For y - 2y - 3y equals 0, y equals 0.
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
Factor the original equation to get (x-7)(x+2)=0, so x=7 or x=-2
many solutions
"x equals 0" is an equality, not an inequality. The question is, therefore, not consistent.
x: x2 - 81 = 0
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
If you mean 2y(2xy)(21)=7yx, then... 12y^2 -y=0 y(12y-1)=0 either y=0 or 12y-1=0, so y=1/12