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Factor the original equation to get (x-7)(x+2)=0, so x=7 or x=-2

Q: How do you solve for x x2-5x-14 equals 0?

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9x2-9x = 0 x2-x = 0 x(x-1) = 0 x = 1 or x = 0

x = 12

Solve this problem -x squared -40x- 80 =0

16x³ - x = 0 By factorization, we obtain: x(16x² - 1) = 0 x(4x - 1)(4x + 1) = 0 Set each term by 0 and solve for x to get: x = 0 and 4x - 1 = 0 and 4x + 1 = 0 x = {0, ±¼}

x * x - 9 = 0 PEMDAS = Multiplication first. What multiplied it self equals nine? 3. So x = 3

Related questions

10x=x 9x=0 x=0

"x equals 0" is an equality, not an inequality. The question is, therefore, not consistent.

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.

X = 1.8

x: x2 - 81 = 0

x=2

9x2-9x = 0 x2-x = 0 x(x-1) = 0 x = 1 or x = 0

x = 12

2x(3x+6) = 0 x = 0 or x = -2

5 ^x = 0 5 = root square 0 5=0

3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3

4x2+50x = 0 4x(x+12.5) = 0 x = 0 or x = -12.5