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It seems there might be a typographical error in your question, as "5x y 18" isn't a standard mathematical expression. If you're trying to solve for (x) or (y) in an equation that involves these variables, please provide the full equation (e.g., (5x + y = 18)). Once you have a complete equation, you can isolate one variable to solve for it.
What else can I help you with?
How do you solve for y 5x 2y3?
To solve for ( y ) in the equation ( 5x = 2y^3 ), you first isolate ( y^3 ) by dividing both sides by 2: ( y^3 = \frac{5x}{2} ). Then, take the cube root of both sides to solve for ( y ): ( y = \sqrt[3]{\frac{5x}{2}} ).
How do you solve systems of equations using substitution?
3(5x-2y)=18 5/2x-y=-1
How do you solve y equals -10 sin 5x?
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5
Y equals 5x plus 18 y equals 2x plus 9?
5x+18 = 2x+9 5x-2x = 9-18 3x = -9 x = -3 and y = 3
What is the equation y equals 5x-3 telling you?
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Solve for y 5x 6y 18?
That's not an equation, it is not solveable.
What is the xintercept for 5x - 4y equals 18?
To find the x-intercept for 5x - 4y = 18, plug in a 0 for the y value and solve for x. 5x - 4(0) = 18 5x = 18 x = 18/5 or 3.6 The line will hit the x-axis at (3.6,0)
What is 5x-y equals 18?
5x-y equals 18 = -13
How do you solve for y 5x 2y3?
To solve for ( y ) in the equation ( 5x = 2y^3 ), you first isolate ( y^3 ) by dividing both sides by 2: ( y^3 = \frac{5x}{2} ). Then, take the cube root of both sides to solve for ( y ): ( y = \sqrt[3]{\frac{5x}{2}} ).
What is the y-intercept for 5x-4y equals 18?
Transform the equation into slope-intercept form: y = mx + b. The intercept is b. 5x - 4y = 18 -4y = 18 - 5x 4y = 5x - 18 y = 5x/4 - 18/4 so the y-intercept is -18/4 or -4.5
How do you solve systems of equations using substitution?
3(5x-2y)=18 5/2x-y=-1
How do you solve y equals -10 sin 5x?
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5
What is the x-intercept for 5x-4y equals 18?
Let y = 0, and solve for x. 5x - 4(0) = 18 5x = 18 divide by 5 both sides x = 18/5 (the x-intercept) Thus, the x-intercept point is (18/5, 0).
Y equals 5x plus 18 y equals 2x plus 9?
5x+18 = 2x+9 5x-2x = 9-18 3x = -9 x = -3 and y = 3
How do you solve 3X plus 2Y equals 16 and 5X plus 3Y-18 equals 4Y by substitution?
First collect like terms in the second equation: 5x - 18 = 4y - 3y ie y = 5x - 18 Substitute this for the term in y in the first equation, getting 3x + 2(5x - 18) = 16 ie 3x + 10x - 36 = 16 ie 13x = 16 + 36 so x = 4 and y = 5 x 4 - 18 ie 2.
How can i solve 5x - 2y 10?
if you mean 5x -2y = 10 then y = 2.5x -5
What is the equation y equals 5x-3 telling you?
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