Can you help me find the value x & Y 3x + 7y = 5 5x-2y = -19
5x - 4y ≥ -203x - 2y ≤ -8y ≥ -3
5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.
5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
write equation in standfrd form y =mx + b where b = y intercept 5x - 2y =20 5x -20 = 2y 5/2 x -10 = y when x = 0 y = -10, the y intercept
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
5x + (3y-x) + (10-2y) = 5x + 3y - x + 10 -2y = 5x - x + 3y - 2y + 10 = 4x + y +10
5X - 2Y = 20 -2Y = -5X + 20 Y = 5/2X - 10 set to 0 and solve for X 5/2X - 10 = 0 5/2X = 10 X = 4 My TI-84 graphs and confirms this
-5x-2y=10
5x - 2y = 10 2y = 5x - 10 y = 2.5x - 5......which is the equation in slope intercept form.
5x 2y = 10
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
Can you help me find the value x & Y 3x + 7y = 5 5x-2y = -19
-2y = 10 2y = -10 y = -5
5y explanaition 5x-5x=0, 0-2y=-2y, -2y+7y=5y
5x - 4y ≥ -203x - 2y ≤ -8y ≥ -3
5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.