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Pythagorean theorum.

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Q: How do you solve for a right triangle?
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Related questions

How do you solve the hypotenuse of triangle APC if angle P is a right angle?

By using trigonometry or using Pythagoras' theorem for a right angle triangle.


The length of the hypotenuse of an isoscales right triangle is 7 meters what is the area of the triangle?

There is not enough information to solve this. You need to know one other length od a side to solve this.


How can you solve for angle A given a right triangle when two sides are given in trigonometric functions?

It depends on the details of the specific triangle.


In triangle ABC B90 b17.5 cm a12.3 cm Solve the triangle?

If it's a right angle triangle then use Pythagoras' theorem to find the 3rd side


What is the length of a of one side of a triangle?

Assuming that you are talking about a right triangle. a2 + b2 = c2 Solve for a a = square root of c2-b2


How do you solve right triangle?

A right triangle has three sides. If you label the sides connected to the right angle side A and side B, and the hypotenuse side C, A^2+B^2=C^2.


How do you solve to find a right triangle of you are given three sides?

Square the two smaller sides and add them together. Take the square root of the answer. If that is the same as the third side then you have a right angled triangle and if not, then you have not.


Which is enough given information needed to solve a right triangle?

Two sides, or two angles + one side.


What can you solve in the Pythagorean theorem?

Given the lengths of two sides of a right triangle, you can find the length of the other side.


Which information cannot be used in conjunction with the law of sines to solve a right triangle?

Yesterday's date cannot be used.


Is it possible to solve a right triangle without using Pythagorean theorem?

Yes simply with a protractor and a measuring device.


How do you find a side of a triangle?

If it's a right triangle, use pythagorean's theorem (a2+b2=c2) to solve it. = If it's an oblique triangle, use the law of sines or cosines (see related link)