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To solve for ( x ) in the equation ((2y + 1)(y - 14) = 0), you can use the zero product property, which states that if the product of two factors is zero, at least one of the factors must be zero. Set each factor to zero: ( 2y + 1 = 0 ) and ( y - 14 = 0 ). Solving these gives ( y = -\frac{1}{2} ) and ( y = 14 ). Thus, the solutions for ( y ) are ( y = -\frac{1}{2} ) and ( y = 14 ).
What else can I help you with?
Why does y plus y equal 2y?
When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
What is 1 plus 1 plus 1X plus 1X plus 1X plus 1Y plus 1Y equals what?
1+1+x+x+x+y+y=2+3x+2y
How do you the solve the equation x equals 2y in terms of x?
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
What are the solutions to the simultaneous equation 3x plus 2y equals 5 and x plus 2y equals 7?
3x + 2y = 5x + 2y = 7Subtract (2) from (1) to give: 3x - x + 2y - 2y = 5 - 7→ 2x = -2→ x = -1Substitute for x in (1)3(-1) + 2y = 5→ -3 + 2y = 5→ 2y = 8→ y = 4Substitute for x and y in (2) to check answer:x + 2y = -1 +2(4) = -1 + 8 = 7 as required. Thus:x = -1y = 4
5x 2y-1 x-1y?
The expression you provided, "5x 2y-1 x-1y," seems to contain some typographical errors or missing operators. If you're looking to simplify or evaluate an expression involving these variables, please clarify the intended operations (e.g., multiplication, addition) and the correct arrangement of terms. For example, it might be interpreted as (5x \cdot (2y - 1) \cdot (x - y)). Please provide more details for a precise answer.
Solve by substition 4x plus 3y equals 1 y equals 2x plus 8?
4x + 3y = 1y = 2x + 8 Take the first part: 4x + 3y = 1y 4x = 1y - 3y 4x = -2y x = -y/2 Substitute x in second part: 1y = 2x + 8 1y = -2y/2 + 8 1y = -1y + 8 2y = 8 y = 4 Substitute y into either part: 1y = 2x + 8 1(4) = 2x + 8 4 - 8 = 2x -4 = 2x x = -2 Therefore: x = -2 y = 4
What is the sum of 5x 2y x-3y?
If you mean: 5x+2y+x-3y then it is 6x-1y
Why does y plus y equal 2y?
When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
Solve the following equations for x and y X 2y -1 4x-3y 18?
X 2y-1 4x-3x=18 X 2y-1 7x=18 X 1y 7x=18 X Y 7x=18 X Y X = 2 4/7 and there is ur anser
What is 1 plus 1 plus 1X plus 1X plus 1X plus 1Y plus 1Y equals what?
1+1+x+x+x+y+y=2+3x+2y
How do you the solve the equation x equals 2y in terms of x?
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
What are the solutions to the simultaneous equation 3x plus 2y equals 5 and x plus 2y equals 7?
3x + 2y = 5x + 2y = 7Subtract (2) from (1) to give: 3x - x + 2y - 2y = 5 - 7→ 2x = -2→ x = -1Substitute for x in (1)3(-1) + 2y = 5→ -3 + 2y = 5→ 2y = 8→ y = 4Substitute for x and y in (2) to check answer:x + 2y = -1 +2(4) = -1 + 8 = 7 as required. Thus:x = -1y = 4
What are the coordinates of the x-intercept -x-2y equals 6?
solve for x -x-2y=6 -x=2y+6 x=-2y-6 plug in y=0 x=-6 when y is 0 therefore the x intercept is (-6,0)
5x 2y-1 x-1y?
The expression you provided, "5x 2y-1 x-1y," seems to contain some typographical errors or missing operators. If you're looking to simplify or evaluate an expression involving these variables, please clarify the intended operations (e.g., multiplication, addition) and the correct arrangement of terms. For example, it might be interpreted as (5x \cdot (2y - 1) \cdot (x - y)). Please provide more details for a precise answer.
Solve for x 3x - 2y equals 6?
x=4 x=4
How do you solve 2x-2y equals 1?
get it to y= -2y = 1 - 2x y = x - 0.5
What is x plus 2y equals 6?
X+2y=6 how to solve? 2y=6-x then y=3-x so y=3-x
