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When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
1+1+x+x+x+y+y=2+3x+2y
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
3x + 2y = 5x + 2y = 7Subtract (2) from (1) to give: 3x - x + 2y - 2y = 5 - 7→ 2x = -2→ x = -1Substitute for x in (1)3(-1) + 2y = 5→ -3 + 2y = 5→ 2y = 8→ y = 4Substitute for x and y in (2) to check answer:x + 2y = -1 +2(4) = -1 + 8 = 7 as required. Thus:x = -1y = 4
x=4 x=4