To solve for ( x ) in the equation ((2y + 1)(y - 14) = 0), you can use the zero product property, which states that if the product of two factors is zero, at least one of the factors must be zero. Set each factor to zero: ( 2y + 1 = 0 ) and ( y - 14 = 0 ). Solving these gives ( y = -\frac{1}{2} ) and ( y = 14 ). Thus, the solutions for ( y ) are ( y = -\frac{1}{2} ) and ( y = 14 ).
When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
1+1+x+x+x+y+y=2+3x+2y
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
3x + 2y = 5x + 2y = 7Subtract (2) from (1) to give: 3x - x + 2y - 2y = 5 - 7→ 2x = -2→ x = -1Substitute for x in (1)3(-1) + 2y = 5→ -3 + 2y = 5→ 2y = 8→ y = 4Substitute for x and y in (2) to check answer:x + 2y = -1 +2(4) = -1 + 8 = 7 as required. Thus:x = -1y = 4
The expression you provided, "5x 2y-1 x-1y," seems to contain some typographical errors or missing operators. If you're looking to simplify or evaluate an expression involving these variables, please clarify the intended operations (e.g., multiplication, addition) and the correct arrangement of terms. For example, it might be interpreted as (5x \cdot (2y - 1) \cdot (x - y)). Please provide more details for a precise answer.
4x + 3y = 1y = 2x + 8 Take the first part: 4x + 3y = 1y 4x = 1y - 3y 4x = -2y x = -y/2 Substitute x in second part: 1y = 2x + 8 1y = -2y/2 + 8 1y = -1y + 8 2y = 8 y = 4 Substitute y into either part: 1y = 2x + 8 1(4) = 2x + 8 4 - 8 = 2x -4 = 2x x = -2 Therefore: x = -2 y = 4
If you mean: 5x+2y+x-3y then it is 6x-1y
When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
X 2y-1 4x-3x=18 X 2y-1 7x=18 X 1y 7x=18 X Y 7x=18 X Y X = 2 4/7 and there is ur anser
1+1+x+x+x+y+y=2+3x+2y
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
3x + 2y = 5x + 2y = 7Subtract (2) from (1) to give: 3x - x + 2y - 2y = 5 - 7→ 2x = -2→ x = -1Substitute for x in (1)3(-1) + 2y = 5→ -3 + 2y = 5→ 2y = 8→ y = 4Substitute for x and y in (2) to check answer:x + 2y = -1 +2(4) = -1 + 8 = 7 as required. Thus:x = -1y = 4
solve for x -x-2y=6 -x=2y+6 x=-2y-6 plug in y=0 x=-6 when y is 0 therefore the x intercept is (-6,0)
x=4 x=4
get it to y= -2y = 1 - 2x y = x - 0.5
X+2y=6 how to solve? 2y=6-x then y=3-x so y=3-x
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x