1+1+x+x+x+y+y=2+3x+2y
-1
Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
x=1y=2x+3y=2*1 + 3y=5
y=5xx2+y2=26Substitute the first equation into the second for y.x2 + (5x)2 = 26x2 + 25x2 = 2626x2 = 26x2 = 1x = SQRT(1) = 1 & -1y = 5*1 = 5y = 5*-1 = -5So the solutions are: (1,5) & (-1, -5)
2x + 1 = 1x + 11Subtract 1x from each side:1x + 1 = 11Subtract 1 from each side:1x = 10
-1
If: x+1+2x = 1x+5 Then: x = 2
x = 0
-1 plus 1 = 0 plus 1 =1
Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
x=1y=2x+3y=2*1 + 3y=5
y=5xx2+y2=26Substitute the first equation into the second for y.x2 + (5x)2 = 26x2 + 25x2 = 2626x2 = 26x2 = 1x = SQRT(1) = 1 & -1y = 5*1 = 5y = 5*-1 = -5So the solutions are: (1,5) & (-1, -5)
1x plus 3x equals 4x. When you combine like terms, you simply add the coefficients of the variables together. In this case, 1 + 3 equals 4, so the final result is 4x.
The expression (1y \times 1y) represents the multiplication of two quantities, each equal to (1y). This can be simplified to (1 \times 1 \times y \times y), which equals (1y^2). Therefore, (1y \times 1y = y^2).
y = 2x + 1 1. Make a table: x = -2; y = -3y = 2x + 1y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1y = 2x + 1y = 2(-1) + 1 = -2 + 1 = -1x = 0; y = 1y = 2x + 1y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3y = 2x + 1y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5y = 2x + 1y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1