21x + 9 = 180 21x = 180 - 9 21x = 171 x = 171/21 x = 8.143
(7x + 7)(x + 2) = 7x2 + 21x + 14
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)
20x + 5 - 20 = 21x + 4 -x = 4 + 15 x = -19
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
21x + 12x -2 = 0 33x -2 = 0 33x = 2 x = 2/33 x = 0.06
I'm assuming that your solving for X. 21x + 12x - 2 = 0 33x - 2 = 0 33x = 2 x = 2/33 x =.06
21x + 9 = 180 21x = 180 - 9 21x = 171 x = 171/21 x = 8.143
(7x + 7)(x + 2) = 7x2 + 21x + 14
10 + 2(x - 1) + 7 x 3x + 1 =10 + 2x - 2 + (7 x 3x) + 1 =10 + 2x - 2 + 21x + 1 =2x + 21x + 10 - 2 + 1 =23x + 9
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)
2x2 + 21x + 49 = (2x + 7)(x + 7)
2x2+21x+49 = (2x+7)(x+7)
20x + 5 - 20 = 21x + 4 -x = 4 + 15 x = -19
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
To factor the expression 21x^35, you need to find the common factors of 21 and x^35. The factors of 21 are 1, 3, 7, and 21. The factors of x^35 are x, x^2, x^3, ..., x^35. Therefore, the factored form of 21x^35 is 21x*x^34 or 21x^(35-1).
(x - 8)(x - 13)