To factor the expression 21x^35, you need to find the common factors of 21 and x^35. The factors of 21 are 1, 3, 7, and 21. The factors of x^35 are x, x^2, x^3, ..., x^35. Therefore, the factored form of 21x^35 is 21x*x^34 or 21x^(35-1).
The greatest common factor (GCF) is 7.
3(7x-6)
x
Since 35 is a factor of 70, it is automatically the GCF.
The GCF/HCF of 35 and 56 is 7.7The GCF is 7.The GCF is 7.
To factor the expression (21x + 35), first identify the greatest common factor (GCF) of the coefficients, which is 7. You can then factor out 7 from the expression: (21x + 35 = 7(3x + 5)). Thus, the factored form is (7(3x + 5)).
To simplify the expression (21x + 35y + 14), we can factor out the greatest common factor (GCF) of the coefficients. The GCF of 21, 35, and 14 is 7. Thus, the expression can be factored as (7(3x + 5y + 2)).
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
put both equations in standard form y - 3x = -5 (equation 1) -7y + 21x = 35 (equation 2) multiply equation 1 by 7 (this is done so either one of your variables will cancel... if both variables cancel then these lines are parallel) 7y - 21x = -35 -7y + 21x = 35 0 = 0 therefore your lines are parallel
Make it equal zero by subtracting 21x from both sides. 20x2 - 21x - 5 factors to (4x - 5)(5x + 1)
The greatest common factor (GCF) is 7.
3(7x-6)
3(7x + 11)
x
It is: 3x*(x+7)
(x - 8)(x - 13)
(2x - 1)(x - 10)