(4^3x)+5=16
4^3x=11
now you can break it down by multiplying out the 3
64^x=11
then you take logs
x= log(11)/6log2.
Or if it's 4^(3x +5) = 16, then you can do it like this: 16 = 4^2, so we have:
4^(3x +5) = 4^2. The bases are the same, in the equation, so the exponents must be equal as well (you can take log-base4 of each side): 3x+5 = 2 --> x = -1
h=16
Solve using the quadratic formula
y=16 x= -4
16 = 7f + 2 14 = 7f 2 = f
-12=m+4 -16=m
x = -8
20
h=16
Solve using the quadratic formula
y=16 x= -4
16 = 7f + 2 14 = 7f 2 = f
-12=m+4 -16=m
16-9+32=16
16
7x+2-2=16-27x = 147x/7 = 14/7x = 2
12y - 4 = 7y + 165y = 20y = 4
It equals postive 16 for more of these prombles go to uglymath.com thank you you ask it I solve it :p