How do you solve for x when 4 to the power of 3x plus 5 equals 16?

Answer 1

(4^3x)+5=16

4^3x=11

now you can break it down by multiplying out the 3

64^x=11

then you take logs

x= log(11)/6log2.

Or if it's 4^(3x +5) = 16, then you can do it like this: 16 = 4^2, so we have:

4^(3x +5) = 4^2. The bases are the same, in the equation, so the exponents must be equal as well (you can take log-base4 of each side): 3x+5 = 2 --> x = -1