Every number you put in it must add up to 15 vertically, horizontally and diagonally.
[ -8 ] [ -1 ] [ -6 ][ -3 ] [ -5 ] [ -7 ][ -4 ] [ -9 ] [ -2 ]The sum of each row, column, and diagonal is -15.
Yes. 7+5, 6+6 4+8, 3+9
6x3=18 3x3=9 18-9=9
45
To create a 3x3 magic square using the numbers 1-9 where each row, column, and diagonal sums to a prime number, you can start by arranging the numbers so that the magic constant (sum of each row, column, and diagonal) is 15, which is not prime. However, to achieve prime sums, you can explore variations by adjusting the placement of specific numbers. For example, one feasible arrangement is to use the numbers 1, 2, 3, 4, 5, 6, 7, 8, and 9 with specific placements to ensure all rows, columns, and diagonals total to prime numbers like 17 or 19, though achieving this with a strict magic square structure may require deviation from classic arrangements.
A normal 3x3 magic square has a sum of 15. So you subtract 3 from each number in the square.
[ 9 ] [ 1 ] [ 6 ] [ 3 ] [ 5 ] [ 7 ] [ 4 ] [ 9 ] [ 2 ]
the 3x3 magic square numbers are... 2 9 4 7 5 3 6 1 8 *american delicacies i now miss especally and 2 7 6 9 5 1 4 3 8 *french help ariving soon in america * = secret message hidden in square
[ -8 ] [ -1 ] [ -6 ][ -3 ] [ -5 ] [ -7 ][ -4 ] [ -9 ] [ -2 ]The sum of each row, column, and diagonal is -15.
Yes. 7+5, 6+6 4+8, 3+9
54 square metres 3x3=9 square metres 6 faces of 9 square metres each 9x6=54
6x3=18 3x3=9 18-9=9
There are 36 unique quadrilaterals in a 3x3 square grid: 14 squares = 9 (1x1) 4 (2x2) 1 (3x3) 22 rectangles = 6 (1x2) 6 (2x1) 6 (3x3) 2 (2x3) 2 (3x2) (the total number of quadrilaterals formed by 3 x 3 pin sets will be larger, i.e. 78)
45
6 side of 3x3 makes 54 square cm.
(3x3x3 - 3x3)/(3 - 3x3) = (27-9)/(3-9) = 18/(-6) = -3 if you mean: 3x3x3 - (3x3)/(3 - 3x3) = 27 - 9/(-6) = 28 1/2
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