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5/8 = tan(x) x = tan-1(5/8) = tan-1(0.625) = 0.558599 + k*pi radians or 32.00538 + k*180 degrees where k is an integer
I am not sure what "tan A 90 degree" means. tan(90 degrees) is an expression that is not defined and so cannot be solved. One way to see why that may be so is to think of tan(x) = sin(x)/cos(x). When x = 90 degrees, sin(90) = 1 and cos(90)= 0 that tan(90) = 1/0 and since division by 0 is not defined, tan(90) is not defined.
tan(x) = sin(x) /cos(x).When x = 90 degrees then cos(x) = 0 so tan(x) requires division by zero - which is not defined.
It's not. The tangent of 180 degrees is zero. Consider tan(x) = sin(x)/cos(x). When x = 180 degrees, sin(x) = 0 and cos(x) = -1 and so tan(x) = 0
That is not correct. "tan x" is a function that depends on the value of "x"; it is not always pi. tan(x) is pi only if 'x' is about 72.3 degrees, 252.3 degrees, or either of these added to a multiple of 360 degrees.
To solve for tan x degree 90 you do a few things. First, if x equals 90, then this equals 1.5597 radian or 89.36 degrees. This is the easiest way to solve tan x degree 90.
5/8 = tan(x) x = tan-1(5/8) = tan-1(0.625) = 0.558599 + k*pi radians or 32.00538 + k*180 degrees where k is an integer
x = tan-1(5) = 78.69 degrees
I am not sure what "tan A 90 degree" means. tan(90 degrees) is an expression that is not defined and so cannot be solved. One way to see why that may be so is to think of tan(x) = sin(x)/cos(x). When x = 90 degrees, sin(90) = 1 and cos(90)= 0 that tan(90) = 1/0 and since division by 0 is not defined, tan(90) is not defined.
You can use the arctangent or the reverse tangent to solve for x, which is denoted by arctan or tan^-1. If tan [x] = 3, then arctan [3] = x. This applies to all trigonometric functions (ex. if sin [x] = 94, then arcsin [94] = x. Punch that into your calculator and the answer will be: arctan [3.0] = 71.565 (degrees) arctan [3.0] = 1.249 (radians)
Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1
tan(x) = sin(x) /cos(x).When x = 90 degrees then cos(x) = 0 so tan(x) requires division by zero - which is not defined.
It's not. The tangent of 180 degrees is zero. Consider tan(x) = sin(x)/cos(x). When x = 180 degrees, sin(x) = 0 and cos(x) = -1 and so tan(x) = 0
How do you solve ln|tan(x)|=ln|sin(x)|-ln|cos(x)|? Well you start by........
That is not correct. "tan x" is a function that depends on the value of "x"; it is not always pi. tan(x) is pi only if 'x' is about 72.3 degrees, 252.3 degrees, or either of these added to a multiple of 360 degrees.
It is NOT equal. Try calculating tan x, and tan 6x, for a few values of "x", on your scientific calculator. Perhaps you are supposed to solve an equation, and see FOR WHAT values of "x" the two are equal?
tan0.15