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5/8 = tan(x) x = tan-1(5/8) = tan-1(0.625) = 0.558599 + k*pi radians or 32.00538 + k*180 degrees where k is an integer
tan(x) = sin(x) /cos(x).When x = 90 degrees then cos(x) = 0 so tan(x) requires division by zero - which is not defined.
It's not. The tangent of 180 degrees is zero. Consider tan(x) = sin(x)/cos(x). When x = 180 degrees, sin(x) = 0 and cos(x) = -1 and so tan(x) = 0
That is not correct. "tan x" is a function that depends on the value of "x"; it is not always pi. tan(x) is pi only if 'x' is about 72.3 degrees, 252.3 degrees, or either of these added to a multiple of 360 degrees.
Tan(90) is infinitely large. Hence it is deemed not solved. Have a look at the graph of the Tan function. Youwill see it passes through '0' at an angle of 45 degrees. At 45 degrees , the graph line is steeper. At 89 degrees it is almost a vertical line. Hence a 90 degrees it is a vertical line and goes off the scale. Hence Tan(90) is unsresolved. Tan(0) = 0 Tan (45) = 1 Tan(60) = 1.7320... Tan(75) = 3.7320... Tan(85) = 11.430... Tan(89) = 57.289.... Tan(89.9) = 572.957... Tan(89.999....) = 57295779.51 Notice how the Tan values becomes larger and larger with increasing angle. Hence Tan(90) = unresolved; off the vertical scale.
Tan(90) is an infinitely large number, and unresolved.
5/8 = tan(x) x = tan-1(5/8) = tan-1(0.625) = 0.558599 + k*pi radians or 32.00538 + k*180 degrees where k is an integer
Tan(90) is infinitely large. Hence it is deemed not solved. Have a look at the graph of the Tan function. Youwill see it passes through '0' at an angle of 45 degrees. At 45 degrees , the graph line is steeper. At 89 degrees it is almost a vertical line. Hence a 90 degrees it is a vertical line and goes off the scale. Hence Tan(90) is unsresolved. Tan(0) = 0 Tan (45) = 1 Tan(60) = 1.7320... Tan(75) = 3.7320... Tan(85) = 11.430... Tan(89) = 57.289.... Tan(89.9) = 572.957... Tan(89.999....) = 57295779.51 Notice how the Tan values becomes larger and larger with increasing angle. Hence Tan(90) = unresolved; off the vertical scale.
You can use the arctangent or the reverse tangent to solve for x, which is denoted by arctan or tan^-1. If tan [x] = 3, then arctan [3] = x. This applies to all trigonometric functions (ex. if sin [x] = 94, then arcsin [94] = x. Punch that into your calculator and the answer will be: arctan [3.0] = 71.565 (degrees) arctan [3.0] = 1.249 (radians)
x = tan-1(5) = 78.69 degrees
Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1
tan(x) = sin(x) /cos(x).When x = 90 degrees then cos(x) = 0 so tan(x) requires division by zero - which is not defined.
It's not. The tangent of 180 degrees is zero. Consider tan(x) = sin(x)/cos(x). When x = 180 degrees, sin(x) = 0 and cos(x) = -1 and so tan(x) = 0
That is not correct. "tan x" is a function that depends on the value of "x"; it is not always pi. tan(x) is pi only if 'x' is about 72.3 degrees, 252.3 degrees, or either of these added to a multiple of 360 degrees.
How do you solve ln|tan(x)|=ln|sin(x)|-ln|cos(x)|? Well you start by........
It is NOT equal. Try calculating tan x, and tan 6x, for a few values of "x", on your scientific calculator. Perhaps you are supposed to solve an equation, and see FOR WHAT values of "x" the two are equal?
tan0.15