2sinx+1 equals 0
factorise it into brackets. The equation is actually x2-6x+0. So into brackets it will be (x-6)(x+0) = 0. From here, to solve the equation, make either of the brackets = 0 by substituting a value for x. In this instance x = 0 or 6.
For y - 2y - 3y equals 0, y equals 0.
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
many solutions
factorise (x-5)(x+4)=0 Hence x= 5 or -4
2sinx+1 equals 0
For y - 2y - 3y equals 0, y equals 0.
factorise it into brackets. The equation is actually x2-6x+0. So into brackets it will be (x-6)(x+0) = 0. From here, to solve the equation, make either of the brackets = 0 by substituting a value for x. In this instance x = 0 or 6.
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
many solutions
"x equals 0" is an equality, not an inequality. The question is, therefore, not consistent.
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
x: x2 - 81 = 0
Solve this problem -x squared -40x- 80 =0
x=2
10x=x 9x=0 x=0