2X - 3Y = -2
4X + Y = 24
-2(2X - 3Y = - 2)
4X + Y = 24
- 4X + 6Y = 4
4X + Y = 24
------------------+
7Y = 28
Y = 4
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insert back into one of the equations ( 4X + Y = 24 will do )
4X +(4) = 24
4X = 20
X =5
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check
2(5) - 3(4) = -2
10 - 12 = -2
-2 = -2
checks
I can see by inspection that the other equation checks also
4
You cannot solve one linear equation in two variables. You need two equations that are independent.
You should use multiplication to solve a system of linear equations by elimination when the coefficients of one variable in the two equations are not easily aligned for direct elimination. This often occurs when the coefficients are not opposites or when they are not easily manipulated to create a zero in one of the variables. By multiplying one or both equations by a suitable value, you can create equal or opposite coefficients, allowing you to eliminate one variable and solve the system more efficiently.
by elimination,substitution or through the matrix method.
By elimination: x = 3 and y = 0
4
You cannot solve one linear equation in two variables. You need two equations that are independent.
You should use multiplication to solve a system of linear equations by elimination when the coefficients of one variable in the two equations are not easily aligned for direct elimination. This often occurs when the coefficients are not opposites or when they are not easily manipulated to create a zero in one of the variables. By multiplying one or both equations by a suitable value, you can create equal or opposite coefficients, allowing you to eliminate one variable and solve the system more efficiently.
by elimination,substitution or through the matrix method.
By elimination: x = 3 and y = 0
Gaussian elimination is used to solve systems of linear equations.
I have never seen the term 'symbolic' used in this way. There are 4 methods used to solve a system of linear equations in two variables. Graphing, Substitution, Elimination, and Cramer's Rule.
The linear system is a math model of a system that is based on the use of a linear operator. The linear system and functional approximation to solve the equation Ax equals b for x by calculating an LU decomposition of A back solving where A equals 2 1 1 and b equals 2 11 cannot be solved, because it is missing more information.
Elimination and substitution are two methods.
Solve the system by the elimination method 5x 5y-13 7x-3y17what is the solution to the system?
a=5: c=4
If you already know that x = -3 and y = 5 what linear equations are you wanting to solve?