4
You cannot solve one linear equation in two unknown variables. You need two independent linear equations.
(2,-2)
By elimination: x = 3 and y = 0
Yes and it works out that x = 3 and y = 4
You cannot solve one linear equation in two variables. You need two equations that are independent.
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
(2,-2)
By elimination: x = 3 and y = 0
Yes and it works out that x = 3 and y = 4
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.
You cannot solve one linear equation in two variables. You need two equations that are independent.
Multiply every term in both equations by any number that is not 0 or 1, and has not been posted in our discussion already. Then solve the new system you have created using elimination or substitution method:6x + 9y = -310x - 6y = 58
Simultaneous equations can be solved using the elimination method.
8840-026
the answer
To solve this system of equations using the elimination method, we need to eliminate one variable by adding or subtracting the two equations. By looking at the equations given (2y-2x-8 = 0 and 3y-18-3x = 0), we can choose to eliminate either the x or y variable. Let's choose to eliminate the x variable: Multiply the first equation by 3 and the second equation by 2 to make the coefficients of x the same: 6y - 6x - 24 = 0 6y - 36 - 6x = 0 Now we can subtract the second equation from the first equation to eliminate x: (6y - 6x - 24) - (6y - 36 - 6x) = 0 Simplify to get -12 = 0, which is a false statement. Therefore, the system of equations is inconsistent and has no solution.
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
There are no disadvantages. There are three main ways to solve linear equations which are: substitution, graphing, and elimination. The method that is most appropriate can be found by looking at the equation.