It can be simplified to 2x^2 +x -6 and factored to (2x-3)(x+2)
-4x-1-3x-4+5 = -7x-1-2x+1+6 -7x = -9x+6 2x = 6 x = 3
If you mean integral[(2x^2 +4x -3)(x+2)], then multiply them out to get: Integral[2x^3+8x^2+5x-6]. This is then easy to solve and is = 2/4x^4+8/3x^3+5/2x^2-6x +c
X=27
The expression simplifies to: -7x-4
It can be simplified to 2x^2 +x -6 and factored to (2x-3)(x+2)
3x - 5x + 4x = -2x +4x = 2x
2x squared minus 5x minus 3 factored is (2x+1)(x-3).
-4x-1-3x-4+5 = -7x-1-2x+1+6 -7x = -9x+6 2x = 6 x = 3
i hope you mean (2x^2 + 21x + 49) you cant solve it its already in its lowest possible form
If you mean integral[(2x^2 +4x -3)(x+2)], then multiply them out to get: Integral[2x^3+8x^2+5x-6]. This is then easy to solve and is = 2/4x^4+8/3x^3+5/2x^2-6x +c
X=27
It can't be solved because the discriminant of this quadratic equation is less than zero
The expression simplifies to: -7x-4
2x + 5 - 5 = 2x. You can not solve for x because this is not an equation.
7x2 -4x -5x2 +2x = 2x2 -2x
4x2 - 9 = (2x + 3)(2x - 3)