-130
x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.
No because the discriminant of the given quadratic expression is less than zero.
x - x2 - 9x + 14 = 0 ; whence, x2 + 8x = 14 , x2 + 8x + 16 = 30 , and x + 4 = ±√30 . Therefore, x = ±√30 - 4 .
x: x2 - 81 = 0
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
You cannot solve, without equating it to something. As given it is just an expression. However it can be factored. x^(2) + 7x +12 ( x + 3)(x + 4) Factored but NOT solved. However, it we equate to 'zero(0)' then it can be solved. ( x + 3)( x + 4) = 0 X + 3 = 0 x = -3 Similarly x + 4 = 0 x = -4 Are the solutions (solved).
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
This is an expression and you do not solve an expression, but you can factor this one.X2 + 3X4X2(1 + 3X2)========
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
(2x)ysquared
(x+5)^2 and therefore x = -5
(2-r)e-rr
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
You will need to use the FOIL formula to solve this type of equation.
x=4 x=0
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
11+2 = 13 and 2*11 = 22 So: x2+13x+22 = (x+2)(x+11) when factored