The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
Equals anything... x is a variable. If that equation was set equal to zero then you could solve for x, but that is not what you have asked.
x2+6x+9 = x+3 x2+6x-x+9-3 = 0 x2+5x+6 = 0 Solve by factoring or with the help of the quadratic equation formula: (x+3)(x+2) = 0 Therefore: x = -3 or x = -2
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
Equals anything... x is a variable. If that equation was set equal to zero then you could solve for x, but that is not what you have asked.
x2+6x+9 = x+3 x2+6x-x+9-3 = 0 x2+5x+6 = 0 Solve by factoring or with the help of the quadratic equation formula: (x+3)(x+2) = 0 Therefore: x = -3 or x = -2
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
please help on this x2+6x+27=
(3, -21)
one