If: x2+7x+12 = 0
Then: (x+4)(x+3) = 0
So it follows: x = -4 and x = -3
* * * * *
True, but that is not using the quadratic formula.
According to the quadratic formula, for the equation ax2 + bx + c = 0:
x = [-b ± sqrt(b2 - 4*a*c)]/(2*a)
= [-7 ± sqrt(72 - 4*1*12)]/(2*1)
= [-7 ± sqrt(49 - 48)]/2
= [-7 ± sqrt(1)]/2
= [-7 ± 1]/2
= [-7 -1]/2 or [-7 +1]/2
=-8/2 or -6/2
= -4 or -3
You can't because it is not a quadratic equation.
Solve using the quadratic formula
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
It can be solved by using the quadratic equation formula.
X= (3/5 , -2)
You can't because it is not a quadratic equation.
Solve using the quadratic formula
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28
It can be solved by using the quadratic equation formula.
X= (3/5 , -2)
The answer of the equation 2a -46a plus 252 = 0 using the quadratic formula is a = 5.25.
By using the quadratic equation formula: x = -5 and x = 3
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
Use the quadratic formula. x = -4.265564 or -0.234436
x = 7/2 and also x = -3/2 by using the quadratic equation formula.
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.