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The question contains no equation (nor inequality) so there is nothing that can be solved.
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
this can not be solved un less with another equation
Yes and it works out that x = 3 and y = 4
-4(7x-3y-z)-(-6)(9x-z+2)
10y= 6y+5+3y 10y=6+9y y=6
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
this can not be solved un less with another equation
by not concentrating on picking your nose when you are in class all day long
Yes and it works out that x = 3 and y = 4
-4(7x-3y-z)-(-6)(9x-z+2)
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
2x-11
y=3(2+x) y= 6+3x Switch x and y x = 6+3y solve for y x-6 = 3y 3y = x-6 y = (x-6)/3 f^-1(x) = (x-6)/3 is the inverse function.
Insufficient information to solve equation, however it can be simplified. Assuming it looks like this 2 (3y+6) The simplified version would be 6y+12