You can't. From that much information, you can't figure out the values for both 'x' and 'y'.
All you can tell is that whatever they turn out to be:
x = 6 - 3y
and
y = x/3 - 2.
In order to calculate what 'x' and 'y' both are, you need another equation besides
x + 3y = 6.
There's nothing wrong with that one, but you need one more.
You need the same number of equations as the number of unknowns.
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
Yes and it works out that x = 3 and y = 4
this can not be solved un less with another equation
2x-11
10y= 6y+5+3y 10y=6+9y y=6
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
Yes and it works out that x = 3 and y = 4
this can not be solved un less with another equation
by not concentrating on picking your nose when you are in class all day long
2x-11
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
6x+7y=-6 3(-2x-3y=2) +________ -2y=0 => y=0 Therefore x=-1
x=1, y=1
It works out that x = 6 and y = 3 or as (6, 3)