7
(-5, 2)
7y + 4 = 5y - 6Subtract 4 from each side:7y = 5y - 10Subtract 5y from each side:2y = -10Divide each side by 2:y = -5
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
X = 0 (zero) Y = -1 (neg 1)
7
(-5, 2)
5y + 7 = 25y = -5y = -1
7y + 4 = 5y - 6Subtract 4 from each side:7y = 5y - 10Subtract 5y from each side:2y = -10Divide each side by 2:y = -5
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
X = 0 (zero) Y = -1 (neg 1)
(2, 2)
The solutions are: x = -2 and y = 4
7x + 5y 7(3) + 5(2) 21 + 10 = 31
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
5y - 2 = 28 - y 5y + y = 28 + 2 6y = 30 y = 30/6 y = 5