62 = 6 x 6 or 36
(x-3)3 = (x-3)*(x-3)*(x-3) =(x-3)*(x2-6x+9) = x3 - 9x2 + 27x - 27
x=18
x to the power of 1 means x
If: x4 = 36 Then: x = 2.4494897428
62 = 6 x 6 or 36
62 = 6 x 6 = 36
the question is to solve (x^2-5x+5)^(x^2-36)=1
(x-3)3 = (x-3)*(x-3)*(x-3) =(x-3)*(x2-6x+9) = x3 - 9x2 + 27x - 27
(√x)^36 = √(x^36) = x^18.
x=18
36 = 3^2 + 3^3
x to the power of 1 means x
Reflexivity is a property of equality, i.e., X = X is always true. Thus -7 raised to the power of 3 equals -7 raised to the power of 3 is true.
It is always negative when raised to an odd power and always positive when raised to an even power -2 to the third power = -2 x -2 x -2 = -8 -2 to the fourth power = -2 x -2 x -2 x -2 = +16
If: x4 = 36 Then: x = 2.4494897428
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4