x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
5 = -2x + 110x - 1,000 5 = 108x - 1,000 1,005 = 108x 335/36 = x
If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42
x = { +6, -6 }
(2x)ysquared
the question is to solve (x^2-5x+5)^(x^2-36)=1
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
x2 = 6482 = 64x = 8
x: x2 - 81 = 0
if x2 + 7 = 37, then x2 = 29 and x = ±√29
5 = -2x + 110x - 1,000 5 = 108x - 1,000 1,005 = 108x 335/36 = x
x2-5x-36 = (x-9(x+4) when factored
If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42
x = { +6, -6 }
8
(2x)ysquared
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9