(10x-3(10x+3)
12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4
-116
No solution in integers, quadratic formula gives roots as 6.73 & 3.27
2x(x−6)(x+1)
2x+8x-2=22 10x-2=22 10x+2=+2 10x=24 10/10=24/10 x=2.4
(10x-3(10x+3)
It can't be solved because the discriminant of this quadratic equation is less than zero
12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4
-116
-10x = -50 Divide both sides by -10 remembering that a minus divided by a minus the quotient then becomes positive: x = 5 So: -10*5 = -50
No solution in integers, quadratic formula gives roots as 6.73 & 3.27
x2-10x-24 = (x+2)(x-12) when factored
It is: 100x^2 -9 = (10x-3)(10x+3) when factored
5x(x - 2)
2x(x−6)(x+1)
X2 + 10X - 13 = 17 add 13 to each side X2 + 10X = 30 halve the linear coefficient ( 10 ), square it and add it to both sides X2 + 10X + 25 = 30 + 25 factor on the left and gather terms on the right (X + 5)2 = 55 (X + 5)2 - 55 = 0 ---------------------------vertex form, (- 5, - 55 ), is the vertex -------------------------------------------[-------------------------------]