x2+5x-24=0(x+8)(x-3)=0x=-8 x=3
(x + 2)(x - 12)
Factors that are multiples of 3 and factors of 24? factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. only 3, 6, 12, and 24 are multiples of 3.
Yes, all the factors of 12 are factors of 24.
21/24 - 4/24 = 17/24
2x+8x-2=22 10x-2=22 10x+2=+2 10x=24 10/10=24/10 x=2.4
3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24] Two factors of -24 which sum to 10 are 12 and -2. So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2) Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
3x2 -14x -24 can be factored as (3x + 4)(x - 6).
x^2 - 10x + 24 You're looking for two factors of 24 that equal 10 (x - 6)(x - 4)
It is: (2x+3)(3x-8) when factored
(x - 12)(x + 2)
The equation x2 - 5x - 24 = 0 has the two solutions 8 and -3 for x.
24
2y2 - 2y - 24 has the factors (2y + 6) and (y - 4) There is a formula, but I always use trial and error. The factors of the non-x element need to be such that they can be added to give the middle element. So when you get 24, then you need to be looking at 2,12 - 3,8 - 4,6 When both the second and third element are minus values then there is a plus and a minus in the factors.
-8x+24 {This answer may be wrong: I think the question was intended to read, "Factor x2 - 10x + 24?" If so, the factors are (x - 6) and (x - 4)}
7x+6 = -3x-24 7x+3x = -24-6 10x = -30 x = -3
82 / 2 = 64/2 = 32 - 8 = 24 - 3 = 21