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Q: How do you sovle for c ab - c 9?

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divide 9 by 17, gives 0.5294

(CD - ab)^2 = (CD - ab)(CD - ab) = c^2 d^2 - 2abcd + a^2b^2 Try it with say a = 4, b = 3, c = 2 & d = 1: Then CD = 2 and ab = 12 so CD - ab = -10 and squared = 100 c^2 = 4 d^2 = 1 so c^2d^2 = 4 x 1 = 4 a^2 = 16 b^2 = 9 so a^2b^2 = 16 x 9 =144 2abcd = 48 giving 4 - 48 + 144 = 100. Shazam!

AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21

ac + cb = ab = 9 2x - 1 + 3x = 9 5x -1 = 9 So 5x = 10 Thereby x =2. Also ac = 3 and cb = 6

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divide 9 by 17, gives 0.5294

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ABA - CA = AB Here A= 1, B = 0 and C = 9 So, ABA = 101, CA = 91 and AB = 10 ABA - CA = 101 - 91 = 10 = AB So these digits are A = 1, B = 0 and C = 9

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a=7 b=9 ab=? ab is the multiplication of a & b there fore the value of ab=7*9=63