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Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
What is One over the square root of three over two?
2 root 3 over 3
1 over 3 square root of 2?
1/3√2 = 1(√2)/3√2(√2) = √2/6
What is the square root of 4 over nine?
2/3
Square root of 9 over 4?
They are +/- 3/2 or +/- 1.5
Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
Can 2 divided by 2 square root 3 be simplified?
Yes, the expression 2 divided by 2 square root 3 can be simplified. To simplify this expression, we need to rationalize the denominator. Multiplying both the numerator and the denominator by the conjugate of the denominator (2 square root 3), we get (2 * 2 square root 3) / (2 * 2 square root 3 * 2 square root 3). This simplifies to 4 square root 3 / 12, which further simplifies to square root 3 / 3.
What is One over the square root of three over two?
2 root 3 over 3
1 over 3 square root of 2?
1/3√2 = 1(√2)/3√2(√2) = √2/6
What is the square root of 4 over 9?
The square root of the fraction 4/9 is either 2/3 or -2/3
What is the square root of 4 over nine?
2/3
What is the answer to 3 over 5 square?
(3/5)2 = 0.36 3 / 52 = 0.12
Square root of 9 over 4?
They are +/- 3/2 or +/- 1.5
Is the square root of 4 over 9 irrational?
sqrt(4/9) = 2/3 = 0.666... Which is NOT irrational .
What is the square root of seven whole number nine over sixteen?
They are -2 3/4 and +2 3/4.
What is the square root 3 plus square root 6 over square root 2?
Because questions can't use punctuation the question is ambiguous. Two possible interpretations of the question, with answers are given below:sqrt(3) + sqrt(6) / sqrt(2) = sqrt(3) + sqrt(6/2) = sqrt(3) + sqrt(3) = 2*sqrt(3)The more likely question is:[sqrt(3) + sqrt(6)]/sqrt(2)Multiply numberator and denominator by sqrt(2) to give[sqrt(2)*sqrt(3) + sqrt(2)*sqrt(6)]/[sqrt(2)*sqrt(2)]=[sqrt(2)*sqrt(3) + 2*sqrt(3)]/2 since sqrt(2)*sqrt(2) = 2= sqrt(3)*[sqrt(2)+1]/2AnswerSquare root three plus square root six is square root 9 over square root two. But nine can be factored out to a perfect three so you would have 3 over square root two.
How do you get 1 divided by the square root of 3 divided by 2?
You would go about this question by first specifying whether there are parenthesis around the square root (3/2) or if it looks like (square root 3)/2 Case A would look something like this. 1/(square root of 3/2) in this case you would multiply both the top and bottom by (square root of 3/2). The bottom portion would become (surprisingly!) 3/2. the top portion would be left as (square root of 3/2). Then, because you are dividing by a fraction, the KEEP CHANGE FLIP rule applies. (square root of 3/2) divided by 3/2 would become (square root of 3/2) multiplied by 2/3 which = 2(square root of 3/2)/3. You can then say that 2 is equal to radical 4 and multiply this by the numerator of the other radical, to get radical 12/2 which equals radical 6. Radical 6 over 3 would be the simplified answer. Case B would look something like this. 1/(square root 3)/2 In this case you would multiply both the top and the bottom by (square root of 3). You would get (square root of 3) divided by 3/2. Then KEEP CHANGE FLIP applies again, and it becomes (square root of 3) multiplied by 2/3. This would then equal 2 radical 3 over 3.
