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Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
What is One over the square root of three over two?
2 root 3 over 3
1 over 3 square root of 2?
1/3√2 = 1(√2)/3√2(√2) = √2/6
What is the square root of 4 over nine?
2/3
Square root of 9 over 4?
They are +/- 3/2 or +/- 1.5
Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
What is One over the square root of three over two?
2 root 3 over 3
Can 2 divided by 2 square root 3 be simplified?
Yes. Multiply both the bottom and top by root 3. Then you have 2 root 3 over two. 2 over 2 simplifies to 1, so the final answer is the square root of 3.
1 over 3 square root of 2?
1/3√2 = 1(√2)/3√2(√2) = √2/6
What is the square root of 4 over 9?
The square root of the fraction 4/9 is either 2/3 or -2/3
What is the square root of 4 over nine?
2/3
What is the answer to 3 over 5 square?
(3/5)2 = 0.36 3 / 52 = 0.12
Square root of 9 over 4?
They are +/- 3/2 or +/- 1.5
Is the square root of 4 over 9 irrational?
sqrt(4/9) = 2/3 = 0.666... Which is NOT irrational .
What is the square root of seven whole number nine over sixteen?
They are -2 3/4 and +2 3/4.
What is the square root 3 plus square root 6 over square root 2?
Because questions can't use punctuation the question is ambiguous. Two possible interpretations of the question, with answers are given below:sqrt(3) + sqrt(6) / sqrt(2) = sqrt(3) + sqrt(6/2) = sqrt(3) + sqrt(3) = 2*sqrt(3)The more likely question is:[sqrt(3) + sqrt(6)]/sqrt(2)Multiply numberator and denominator by sqrt(2) to give[sqrt(2)*sqrt(3) + sqrt(2)*sqrt(6)]/[sqrt(2)*sqrt(2)]=[sqrt(2)*sqrt(3) + 2*sqrt(3)]/2 since sqrt(2)*sqrt(2) = 2= sqrt(3)*[sqrt(2)+1]/2AnswerSquare root three plus square root six is square root 9 over square root two. But nine can be factored out to a perfect three so you would have 3 over square root two.
How do you get 1 divided by the square root of 3 divided by 2?
You would go about this question by first specifying whether there are parenthesis around the square root (3/2) or if it looks like (square root 3)/2 Case A would look something like this. 1/(square root of 3/2) in this case you would multiply both the top and bottom by (square root of 3/2). The bottom portion would become (surprisingly!) 3/2. the top portion would be left as (square root of 3/2). Then, because you are dividing by a fraction, the KEEP CHANGE FLIP rule applies. (square root of 3/2) divided by 3/2 would become (square root of 3/2) multiplied by 2/3 which = 2(square root of 3/2)/3. You can then say that 2 is equal to radical 4 and multiply this by the numerator of the other radical, to get radical 12/2 which equals radical 6. Radical 6 over 3 would be the simplified answer. Case B would look something like this. 1/(square root 3)/2 In this case you would multiply both the top and the bottom by (square root of 3). You would get (square root of 3) divided by 3/2. Then KEEP CHANGE FLIP applies again, and it becomes (square root of 3) multiplied by 2/3. This would then equal 2 radical 3 over 3.
