Because questions can't use punctuation the question is ambiguous. Two possible interpretations of the question, with answers are given below:
sqrt(3) + sqrt(6) / sqrt(2) = sqrt(3) + sqrt(6/2) = sqrt(3) + sqrt(3) = 2*sqrt(3)
The more likely question is:
[sqrt(3) + sqrt(6)]/sqrt(2)
Multiply numberator and denominator by sqrt(2) to give
[sqrt(2)*sqrt(3) + sqrt(2)*sqrt(6)]/[sqrt(2)*sqrt(2)]
=[sqrt(2)*sqrt(3) + 2*sqrt(3)]/2 since sqrt(2)*sqrt(2) = 2
= sqrt(3)*[sqrt(2)+1]/2
AnswerSquare root three plus square root six is square root 9 over square root two. But nine can be factored out to a perfect three so you would have 3 over square root two.if you take out the word ''quantity'' your answer is 25.02725024
24
It is 2*sqrt(5).
2 root 3 over 2, so square root of 3
2 times the Square root of 3 + 4
The square root of 2 plus the square root of 2 is equal to twice the square root of 2, therefore the correct answer is: 2(√2) or √8
if you take out the word ''quantity'' your answer is 25.02725024
Square root of 2 = 1.414213562... Square root of 7 = 2.645751311... The sum is 4.059964873...
24
root 3 - 1 all over 2
It is 2*sqrt(5).
2 root 3 over 2, so square root of 3
square root of 4x is 2 times square root of x, so answer is square root of x times 3 since it is 2 square roots of x plus one of them
The value of 1 plus the square root of 2 is approximately 2.41.
3.14626437 (Pi)
154.242641
2 times the Square root of 3 + 4