6xyz(3x + 2y + z)
4z squared (z+4) (z+4)
(z-9)(z+3
No.
re x and y and hypotenuse z then x squared + y squared = z squared If you know x and z, then y sqrd = z sqrd-x sqrd and thus y = square root of (z sqrd -x sqrd)
This is a difference of two sqaures. 49y2 - z2 = (7y - z)(7y + z)
6xyz(3x + 2y + z)
4z squared (z+4) (z+4)
x squared + y squared = z squared.
(z=-3) and (z=7)
(z-9)(z+3
No.
re x and y and hypotenuse z then x squared + y squared = z squared If you know x and z, then y sqrd = z sqrd-x sqrd and thus y = square root of (z sqrd -x sqrd)
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
z
89
4x cubed y cubed z divided by x negative squared y negative 1 z sqaured = 4