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How many sides does an irregular polygon have when its interior angles add up to 5040 degrees showing work?
It is: (5040+360)/180 = 30 sides
How do you work out an interior angle on an irregular polygon?
You have to measure it - or have a lot more information that is given in this question.
How do you work out an interior angle on a polygon when it has n sides?
The sum of the interior angles of a polygon with n sides is 180*(n-2) degrees. If the polygon is equiangular (ie all its angles are the same) then each of them is 180*(n-2)/n degrees.
What are the total diagonals in an irregular polygon whose interior angles add up to 1980 degrees showing all work?
Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
Work out the exterior and interior angles of a regular polygon with 8 sides?
Each exterior angle 45 degrees Each interior angle 135 degrees
How many sides does an irregular polygon have when its interior angles add up to 5040 degrees showing work?
It is: (5040+360)/180 = 30 sides
How do you work out an interior angle on an irregular polygon?
You have to measure it - or have a lot more information that is given in this question.
How do you work out an interior angle on a polygon when it has n sides?
The sum of the interior angles of a polygon with n sides is 180*(n-2) degrees. If the polygon is equiangular (ie all its angles are the same) then each of them is 180*(n-2)/n degrees.
How do you work out the angles in a polygon?
There is no way to work out the angles in a general polygon. The sum of the interior angles of a polygon, with n sides, is (n-2)*pi radians [or (n-2)*180 degrees]. Therefore, if you know the measure of n-1 angles, you can work out the size of the nth angle.Alternatively, if the polygon is one of the rare type - a regular polygon - then all its angles are equal. In that case, you can divided the above sum by n.
Is there a regular polygon with angles of 158 degree?
Nope, sorry honey. A regular polygon has all interior angles equal, so if one angle is 158 degrees, all angles would have to be 158 degrees. But the sum of interior angles in a polygon is (n-2)*180 degrees, where n is the number of sides. So for a regular polygon with angles of 158 degrees, you'd need n=11 sides, which doesn't work because a regular polygon must have at least 3 sides.
Work out the exterior and interior angles of a regular polygon with 8 sides?
Each exterior angle 45 degrees Each interior angle 135 degrees
What are the total diagonals in an irregular polygon whose interior angles add up to 1980 degrees showing all work?
Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
How do you work out the interior and exterior angles of a regular polygon?
If the polygon has n sides (or vertices) each exterior angle is 360/n. Each interior angle = 180 - exterior angle = 180 - 360/n
What is the total interior angles for a 56 sided shape?
The equation for the total interior angles of a polygon is (n-2)x180. In this case, the shape has 56 sides. Thus, to work out the total interior angles of the shape you do: (56-2)x180 =54x180 =9,720. Therefore the total interior angles for a 56 sided shape is 9,720.
What do the angles inside a heptagon add up to Show me the work?
The sum of the interior angles of a polygon is (n-2)*180 degrees = 5*180 = 900 degrees.
How do you work out the amount of sides o a exterior angle that is 10?
To work out the number of sides, this polygon has to be a regular polygon in which all the interior angles are the same A regular polygon has exterior angles of 10o, therefore it must have interior angles of 180o - 10o = 170o Total interior angles = (Number of sides - 2)x180o Therefore each interior angle = [(Number of sides - 2)x180o]/Number of sides n = number of sides 170o = [(n-2)x180o]/n 170no = 180no-360o 360o = 10no n = 360o/10o n = 36
How do you work out the exterior and interior angles of a regular polygon with W sides?
Exterior angle regular polygon = 360° ÷ number of sides = 360° ÷ W Interior angle regular polygon = 180° - exterior angle regular polygon = 180° - (360° ÷ number of sides ) = 180° - (360° ÷ W)
