It is: (5040+360)/180 = 30 sides
You have to measure it - or have a lot more information that is given in this question.
The sum of the interior angles of a polygon with n sides is 180*(n-2) degrees. If the polygon is equiangular (ie all its angles are the same) then each of them is 180*(n-2)/n degrees.
Each exterior angle 45 degrees Each interior angle 135 degrees
Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
It is: (5040+360)/180 = 30 sides
You have to measure it - or have a lot more information that is given in this question.
The sum of the interior angles of a polygon with n sides is 180*(n-2) degrees. If the polygon is equiangular (ie all its angles are the same) then each of them is 180*(n-2)/n degrees.
There is no way to work out the angles in a general polygon. The sum of the interior angles of a polygon, with n sides, is (n-2)*pi radians [or (n-2)*180 degrees]. Therefore, if you know the measure of n-1 angles, you can work out the size of the nth angle.Alternatively, if the polygon is one of the rare type - a regular polygon - then all its angles are equal. In that case, you can divided the above sum by n.
Each exterior angle 45 degrees Each interior angle 135 degrees
If the polygon has n sides (or vertices) each exterior angle is 360/n. Each interior angle = 180 - exterior angle = 180 - 360/n
Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
The equation for the total interior angles of a polygon is (n-2)x180. In this case, the shape has 56 sides. Thus, to work out the total interior angles of the shape you do: (56-2)x180 =54x180 =9,720. Therefore the total interior angles for a 56 sided shape is 9,720.
The sum of the interior angles of a polygon is (n-2)*180 degrees = 5*180 = 900 degrees.
To work out the number of sides, this polygon has to be a regular polygon in which all the interior angles are the same A regular polygon has exterior angles of 10o, therefore it must have interior angles of 180o - 10o = 170o Total interior angles = (Number of sides - 2)x180o Therefore each interior angle = [(Number of sides - 2)x180o]/Number of sides n = number of sides 170o = [(n-2)x180o]/n 170no = 180no-360o 360o = 10no n = 360o/10o n = 36
Exterior angle regular polygon = 360° ÷ number of sides = 360° ÷ W Interior angle regular polygon = 180° - exterior angle regular polygon = 180° - (360° ÷ number of sides ) = 180° - (360° ÷ W)
The sum of the interior angles (the angles of a polygon is equal to the 180*(n-2), where n is the number of sides. For example, if a polygon has 5 sides the sum of the angles is 180*(5-2), which is 540 degrees. The sum of the exterior angles (the angles on the outside of the polygon made by extending a side and measuring the angle between the extension and the nearest side) is always equal to 360 degrees.