If the 3 sides are x, y and z then let s = (x+y+z)/2
Area = sqrt[s*(s-x)*(s-y)*(s-z)] sq cm.
220 cm2
Using trigonometry the angles of the triangle are 56.09 degrees, 97.09 degrees and 26.81 degrees with an area of 22.82 square cm all rounded to two decimal places.
5 x 10 = 50cm2
The area of a rectangle of sides 9cm and 10cm is:9cm x 10cm = 90cm2This is equivalent to 0.009m2
There are 5 linear measures given. If that implies that the shape is a pentagon, there is no way to answer the question with out additional information about the angles in the pentagon. A triangle is the only polygonal shape whose area is uniquely determined by the length of its sides.
55 square centimeters
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
200 sq. cm.
220 cm2
Using trigonometry the angles of the triangle are 56.09 degrees, 97.09 degrees and 26.81 degrees with an area of 22.82 square cm all rounded to two decimal places.
half the base an divide the area by that
To find the area of a triangle, you use the formula: Area = 1/2 * base * height. Plugging in the values, we get Area = 1/2 * 10cm * 15cm = 75 square cm. Therefore, the area of the triangle with a base of 10cm and a height of 15cm is 75 square cm.
30cm
3 4
5 x 10 = 50cm2
The area of a rectangle of sides 9cm and 10cm is:9cm x 10cm = 90cm2This is equivalent to 0.009m2
The area of triangle is : 60.0