200 sq. cm.
If the sides are 10cm, 17cm and 21cm, the three angles are approx 28, 53 and 99 degrees. It is an obtuse angled triangle.
yes
a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm This simplifies down to 3b + 10cm = 46cm subtract 10cm from both sides of the equation 3b + 10cm - 10cm = 46cm - 10cm 3b = 36cm Then divide each side of the equation by 3 3b ÷ 3 = 36cm ÷ 3 b = 12cm Subsitute b back into a = b +5cm a = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm
To find the area of a triangle, you use the formula: Area = 1/2 * base * height. Plugging in the values, we get Area = 1/2 * 10cm * 15cm = 75 square cm. Therefore, the area of the triangle with a base of 10cm and a height of 15cm is 75 square cm.
The length of the two equal sides is not enough information to uniquely determine the length of the base.With sides of 10 cm, you can draw a triangle with anybase that's longer than zero and shorter than 20 cm.The height can be anything taller than zero and shorter than 10 cm.
Using Pythagoras' theorem the longest side which is the hypotenuse works out as 10cm
If the sides are 10cm, 17cm and 21cm, the three angles are approx 28, 53 and 99 degrees. It is an obtuse angled triangle.
It is a right angle triangle and its largest angle is 90 degrees
if it is a scalene triangle yes scalene triangle have no congruent sides and angles
No because the 3 sides of an equilateral triangle are equal in length
yes
So?
Size or internal angles?
14.14 cm (rounded)
No, it is not possible to draw a triangle with sides of 150 cm, 10 cm, and 10 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 10 cm + 10 cm is not greater than 150 cm.
The top is also 10cm, the right is 5cm and so is the left.
one side equals 5 another equals 4 and the last is 1 (a=bh/2)