Arthur Pythagoras: Diagonal = sqrt (square of side 1 + square of side 2)
In your case D = sqrt (2 x 2500) = 70.71cm
Addendum: If it is a square, as is your case, multiply the length of one side by the square root of 2:
1.4142 * 50.00 cm = 70.71 cm.
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Pythagoras! If AB = 100m and BC = 75cm then AC = sqrt (10000 + 5625) = 125
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
Two equal size right angle triangles.
50cm - 20cm roughly, why do you want to know this anyway?
d = 11.5 inches.
Pythagoras! If AB = 100m and BC = 75cm then AC = sqrt (10000 + 5625) = 125
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
Two equal size right angle triangles.
small= 70cm by 50cm med= 90cm by 50cm large= 1m by 67cm. I hope they are the answers you were looking for.
squares or more rectangles depending on the size of the rectangle to begin with and how you cut it.
13 cm Solved with the help of the quadratic formula and Pythagoras' theorem.
50cm - 20cm roughly, why do you want to know this anyway?
A meerkat can weigh about 2 pounds and are 20cm to 50cm including their tail.
diagonal
4 tiles.4 tiles.4 tiles.4 tiles.