In this case, it's probably faster to simply solve it by completing the square than by trying to find it's factors:
x2 + 25x - 10974 = 0
x2 + 25x = 10974
x2 + 25x + 625/4 = 10974 + 625/4
(x + 25/2)2 = 10974 + 156.25
x + 25/2 = ± √11130.25
x + 25/2 = ± √44521 / 2
x = (-25 ± √44521) / 2
x = (-25 ± 211) / 2
x = 93, -118
This tells us that if we had factored the equation out in the first place, we would have wound up with:
(x - 93)(x + 118) = 0
To solve the equation x^2 + 25x - 10974 = 0, you can use factoring or the quadratic formula. Factoring may not be straightforward in this case, so let's use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. Using the coefficients from the equation, -b would be -25, a would be 1, and c would be -10974. Substituting these values into the formula will give you two possible solutions for x.
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
x2 + 10x + 21 = (x + 3)(x + 7)
-2
-7.5?
(2-r)e-rr
x2 + x2 = 2x2
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
It equals x2 - 34
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
if x2 + 7 = 37, then x2 = 29 and x = ±√29
x2 + 10x + 21 = (x + 3)(x + 7)
-2
-7.5?
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
X2 or 2 times x?
(2-r)e-rr
no