Centre of circle: (2, 1.25) Slope of line: 9/4 Equation of line: y-1.25 = 9/4(x-2) => 4y-5 = 9x-18 => 4y = 9x-13
1/2 , 3/2
Add the two equations and get 4x = 12 so x = 3 and y = -1
8x + 10 = 3x +145x = 4x = 4/5 = 0.8Improved answer:8x+10 = 4x+148x-4x = 14-104x = 4x = 1
7+8x-5 = 8x+7-5x Subtract 7 from both sides: 8x-5 = 8x-5x Subtract 8x from both sides: -5 = -5x Divide both sides by -5: x = 1 So the equation implies x = 1
-4x + 4y = 1
Equations: y = x+4 and x^2 +y^2 -8x +4y = 30 It appears that the given line is a tangent line to the given circle and the point of contact works out as (-1, 3)
No.
x=4y+1 x=4y-1 No,they have different solutions.
(1, 1)
(1, 1)
No.
(-1, 5)
(-1, 5)
(2, -1)
8x = 4y + 3 x = 0,5y + 3/8We fill this out in the second formula:5(0,5y + 3/8) +2y = 34,5y = 3 - 15/8y = 2/3 - 15/36 = 24/36 - 15/36 = 9/36 = 1/4X = 1/8 *1+3 = 1/2
x=1