A question about the nth term of a sequence, which does not give you the formula for the nth term, can only contain a finite number of terms. The issue then is to find a function that will generate these numbers. Now, given any set of n numbers, it is always possible to find infinitely many polynomials of order n such that the polynomial is the formula for the nth term. Furthermore, there will be at least one polynomial of order (n-1) that will meet the requirements. There will be non-polynomial functions as well. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example, given the sequence 1, 3, 5, 7, 9, 11, ... what do you think is the formula for the nth term?
It could be t(n) = 2n - 1
But, it could also be
u(n) = (n^6 - 21*n^5 + 175*n^4 - 735*n^3 + 1624*n^2 - 1524*n + 600)/120, or any of an infinite number of 6th degree polynomials in n.
The next terms for these two formulae would be t(7) = 13 and u(7) = 19.
But you were not given the 7th term so you do not know which formula is correct! If the 7th term is given, you can find infinitely many 7th degree polynomials that will work.
Then the only solution is Occam's razor: go for the answer that looks simplest. Or go for one that you like!
No, it will be a formula, because "the nth term" means that you have not defined exactly which term it is. So, you make a formula which works for ANY term in the sequence.
It is: nth term = 35-9n
The Nth term in the series is [ 2N ] .
multiplies by 2
please help
The Nth term formula for oblong numbers is N = N(N+1)
No, it will be a formula, because "the nth term" means that you have not defined exactly which term it is. So, you make a formula which works for ANY term in the sequence.
It is: nth term = 35-9n
The nth term of the sequence is expressed by the formula 8n - 4.
nth term = 5 +8n
The nth term is: 5-6n
The Nth term in the series is [ 2N ] .
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
it is 6n
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
8