Q: How do you write a polynomial that represents the area of a rectangle with the length is 8 centimeters less than 3 times the width?

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let x be the width let x+3 be the length The area of a rectangle is length X width Area=(x)(x+3) =x^2+3x

The length is (18 centimeters) minus (the width)

3 cm

Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter

the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle

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let x be the width let x+3 be the length The area of a rectangle is length X width Area=(x)(x+3) =x^2+3x

30 ft

The length is (18 centimeters) minus (the width)

21cm3

3 cm

150 cm !

46 centimeters

In a rectangle, the area is calculated by multiplying length x width. If (for example) both length and width are in centimeters, the area will be in square centimeters.

Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter

the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle

77cm!

The width of the rectangle is 4 cm