let x be the width let x+3 be the length The area of a rectangle is length X width Area=(x)(x+3) =x^2+3x
The length is (18 centimeters) minus (the width)
3 cm
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
let x be the width let x+3 be the length The area of a rectangle is length X width Area=(x)(x+3) =x^2+3x
30 ft
The length is (18 centimeters) minus (the width)
21cm3
3 cm
150 cm !
46 centimeters
In a rectangle, the area is calculated by multiplying length x width. If (for example) both length and width are in centimeters, the area will be in square centimeters.
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
77cm!
The width of the rectangle is 4 cm