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Q: How do you write a situation that can be represented by 6n 4?

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14

12m + 9n - 4 - 10m + 6n = 2m + 15n - 4

6n - 4 - 3 = 3n + 10 + 4n -7 = 7n - 6n + 10 -17 = n

6n + 4 = 40(Minus 4 on both sides)6n = 40 - 46n = 36(Divide by 6 on both sides)n = 36/6= 6

4

Related questions

6n take-away 4 = 2

I assume that you mean n = 3 6n + 4 = 6(3) + 4 = 18 + 4 = 22

14

12m + 9n - 4 - 10m + 6n = 2m + 15n - 4

6n - 4 - 3 = 3n + 10 + 4n -7 = 7n - 6n + 10 -17 = n

6n + 4 = 40(Minus 4 on both sides)6n = 40 - 46n = 36(Divide by 6 on both sides)n = 36/6= 6

4

The answer is: n=4.

6n=24 you divide both sides by 6 to leave n by itself. the answer is 4.

f(n) = 14 - 6n -6n+20

So far, the best and most general pattern found is that, over three, all prime numbers are of the form 6n +/- 1. In other words, they're either 6n - 1 or 6n + 1, for some n. Here is why this is true. We could do a proof by contradiction and assume that all the natural numbers greater than or equal to 5 are prime. (of course they are not!) We start with5 which is 6-1. The numbers would then be 6n - 1, 6n, 6n + 1, 6n + 2, 6n + 3, 6n + 4, and 6n + 5 for some natural number n. If it is 6n, then the number is divisible by 6. When it is 6n + 2, the number is the same as 2(3n+1) so it is divisible by 2. Consider 6n + 3, the number is 3(2n+1), so it is divisible by 3. Last look at 6n + 4, the number is divisible by 2, for it's 2(3n + 2). Therefore all numbers of the form 6n, 6n + 2, 6n + 3, and 6n + 4 are not prime. The only possibilities this leaves are 6n - 1 and 6n + 1. This entire thing can be written more elegantly with congruences, but the goal here was simplicity! There are many other patterns in primes. See the attached link to see them.

6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3