Area: 15ab
Perimeter: 2(3a+5b) or as 6a+10b
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
The rectangle would be shaped like any other rectangle. To find the perimeter, add all four sides together. perimeter = 50ft + 50ft + 25ft + 25ft = 150ft
The perimeter of a rectangle is length + width x 2 = perimeter. * * * * * That is misleading since that would be evaluated as L + W2 or L + 2W. The perimeter of any polygon is the sum of the lengths of its sides. A rectangle has two sides of the same length (L) and the other two of the same width (W). So the perimeter is 2*L + 2*W or 2*(L + W).
In the case of a rectangle, you would maximize the area given the perimeter by making the dimensions equal. In other words, you would make the rectangle into a square. However, to truly maximize the area, you would make the perimeter a perfect circle.
Yes, the perimeter of a rectangle can be larger than its area. For example, consider a rectangle with dimensions 1 unit by 1 unit, which has a perimeter of 4 units and an area of 1 square unit. As the rectangle's dimensions change, especially when one dimension is much larger than the other, the perimeter can exceed the area even more significantly.
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
No. The length is the measurement of the distance from the bottom to the top of the rectangle, or from one side to the other side. The perimeter is the distance all the way around the rectangle.
The formula for the perimeter of a rectangle is: p = 2(l + w) In other words, just add all four sides. You can't calculate the perimeter of the rectangle if you know only the length.
The rectangle would be shaped like any other rectangle. To find the perimeter, add all four sides together. perimeter = 50ft + 50ft + 25ft + 25ft = 150ft
Perimeter = 25+36+25+36 = 122 units of measurement Use Pythagoras' theorem to find the other side of the rectangle
The perimeter and area don't depend on each other. Knowing one doesn't tell you the other. -- A circle with perimeter (circumference) of 20 cm has area of 31.83 cm2. -- A square with perimeter of 20 cm has area of 25 cm2 . -- A (9 x 1) rectangle has perimeter of 20 cm and area of 9 cm2 . -- A (8 x 2) rectangle has perimeter of 20 cm and area of 16 cm2 . -- A (7 x 3) rectangle has perimeter of 20 cm and area of 21 cm2 . -- A (6 x 4) rectangle has perimeter of 20 cm and area of 24 cm2 .
The perimeter of a rectangle is length + width x 2 = perimeter. * * * * * That is misleading since that would be evaluated as L + W2 or L + 2W. The perimeter of any polygon is the sum of the lengths of its sides. A rectangle has two sides of the same length (L) and the other two of the same width (W). So the perimeter is 2*L + 2*W or 2*(L + W).
no because one rectangle may be 3x4 which the perimeter is 14 and one rectangle may be 5x2 which as well equals 14
In the case of a rectangle, you would maximize the area given the perimeter by making the dimensions equal. In other words, you would make the rectangle into a square. However, to truly maximize the area, you would make the perimeter a perfect circle.
There is no formula for a rectangle. There are formula for calculating its area, perimeter or length of diagonals from its sides, or it is possible to calculate the length of one pair of sides given the other sides and the area or perimeter, or the two lots of sides given area and perimeter and so on.
Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.