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What is another way to write x2 over y3?
x^2/y^3 = x^2*y^(-3)
When can a polynomial is said to be sum or difference of two cubes?
When it is of the form x3 + y3 or x3 - y3. x or y can have coefficients that are perfect cubes, or even ratios of perfect cubes eg x3 + (8/27)y3.
What is the answer to y2 x y?
Y3
What is x12multiply y3 multiply y3 multiply x-2 equal?
12x2 - 24x + 9y
Is the y3 equals x is linear function?
no
What is another way to write x2 over y3?
x^2/y^3 = x^2*y^(-3)
When can a polynomial is said to be sum or difference of two cubes?
When it is of the form x3 + y3 or x3 - y3. x or y can have coefficients that are perfect cubes, or even ratios of perfect cubes eg x3 + (8/27)y3.
If y equals 3 then y3 y3-y equals?
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
What is the standard equation of the parabola y3(x-4)2-22?
the standard form of the equation of a parabola is x=y2+10y+22
What is the answer to y2 x y?
Y3
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
What is x12multiply y3 multiply y3 multiply x-2 equal?
12x2 - 24x + 9y
Is the y3 equals x is linear function?
no
How do you simplify 10xy3 times 8x5y3?
10xy3 * 8x5y3 = (10*8)*(x*x5)*(y3*y3) = 80x6y6
Identify the variable expression that is not a polynomial?
x-9+y3
How do you find the equation when all zeros are given?
Let's say y1, y2, and y3 are zeros. Set up an expression like this (x-y1)(x-y2)(x-y3) [This is factored form] and then multiply carefully. That works with any number of roots. If 0 is a root, add an x by itself to the beginning of the factored form expression. Also, imaginary roots come in twos. Therefore, if given i as a root, you need (x-i)(x+i). If you have something in x + yi form for a root, you'll need the complex conjugate. That would make (x-(a+bi))(x-(a-bi))
Divide x by y cube the answer and decrease it by f?
The expression is x/y3 - f.
