If you have like terms then to multiply you add the exponents and to divide you subtract.So, x2 * x3 = x5 and y7 / y5 = y2Also, for example, 2x2 * x3 = 2x5 (we can do this as the terms are like; x's only)But if you do not have like terms then this does not apply.For example, x2 * y3 does not equal xy5.
x^2/y^3 = x^2*y^(-3)
the answers is d
8 x y1.5 sqrt(2)
the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3
X2+Y3+15 All you can do is simplify it.
If you have like terms then to multiply you add the exponents and to divide you subtract.So, x2 * x3 = x5 and y7 / y5 = y2Also, for example, 2x2 * x3 = 2x5 (we can do this as the terms are like; x's only)But if you do not have like terms then this does not apply.For example, x2 * y3 does not equal xy5.
x^2/y^3 = x^2*y^(-3)
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
(x2 - xy + y2)(x + y)
the answers is d
n = x2 + 1 n = y3 - 1 x2 + 1 = y3 - 1 x2 = y3 - 2 x = (y3 - 2).5 This means that you need to find all cubes where subtracting 2 yields a square: Cubes: 1, 8, 27, 64, 125,... (-2): -1, 6, 25, 62, 123,... (27,25) works. n = 26
√(49x4y6) = √49√x4√y6 = 7*x2*y3
8 x y1.5 sqrt(2)
Not sure. There is no particular name for x2 and 2xy (both include x) in x2 + 2xy + y2 + y3
the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3
#include<stdio.h> #include<conio.h> void main() { int x1, x2, x3, y1, y2, y3 ; printf("\nEnter the Co-ordinates of first point(x1,y1)"); scanf("d",&1x, &y1); printf("\nEnter the Co-ordinates of 2nd point(x2,y2)"); scanf("d",&x2, &y2); printf("\nEnter the Co-ordinates of 3rd point(x3,y3)"); scanf("d",&x3, &y3); if( (y2-y1)/(x2-x1)==(y3-y2)/(x3-x2) ) printf("The three points lie on straight line"); else printf("The three points do not lie on straight line"); getch(); }