H = 1/2 G T2 = 1/2 (32.2) (1.5)2 = 36.23 feet
Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters
It is 4 square meters
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
Well, 2 meters.
Hold the egg 3 meters above the floor and drop it. It will fall (the first) 2 meters without breaking. Sure, it will break when it hits the floor, but THAT is at THREE meters- and you said TWO.
the earth doesnt fall.
2 meters highs
writing and literature
The time it takes for a 2-kg ball to fall from a height of 2 meters can be calculated using the formula t = sqrt(2h/g), where t is the time, h is the height (2 meters), and g is the acceleration due to gravity (approximately 9.81 m/s^2). Substituting the values, we find that it will take about 0.64 seconds for the ball to fall.
To calculate the vertical fall over a horizontal distance at a given angle, you can use trigonometry. In this case, the fall at 2 degrees over 6 meters can be calculated using the formula: vertical fall = horizontal distance * tan(angle). Plugging in the values, the vertical fall would be approximately 0.21 meters, or 21 centimeters.
It Depends on the height of the window 2 Storeys = Vet is needed Over 2 Storeys = Dog will not survive the fall
H = 1/2 G T2 = 1/2 (32.2) (1.5)2 = 36.23 feet
Only one sperm fertilises an egg in normal cases, abnormally there are chances of fertilization by 2 or more sperm cells but such a zygote usually does not survive.
In the tenth second, an object in free fall will have fallen approximately 490 meters. This is because the distance fallen increases by 1/2 the acceleration of gravity each second squared (9.8 m/s^2).
Objects in free fall will be accelerating, so you need to know which second that you are interested in, and the acceleration from gravity (9.8 meters per sec2) The formula for distance is: d = v0*t + (1/2)*a*t2. Where v0 is the initial velocity, t is time, and a is acceleration.
Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters