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To calculate the fall over a distance of 1.8 meters for a 5-degree angle, you can use the formula: fall = distance × sin(angle). In this case, fall = 1.8 meters × sin(5 degrees) ≈ 1.8 × 0.0872 ≈ 0.157 meters, or about 15.7 centimeters.
To calculate the fall of a 2-degree roof over a distance of 6 meters, you can use the formula: fall = distance × tan(angle). The tangent of 2 degrees is approximately 0.0349. Therefore, the fall over 6 meters would be 6 × 0.0349, which is about 0.2094 meters, or approximately 21 centimeters.
To calculate the fall (or slope) of a 3-degree roof over a distance of 2 meters, you can use the formula: fall = distance × tan(angle). In this case, the fall would be approximately 2 meters × tan(3 degrees), which equals about 0.105 meters, or 10.5 centimeters. Thus, the roof would fall approximately 10.5 cm over the 2-meter span.
To calculate the fall (or rise) for an 11-degree roof over 1 meter, you can use the tangent of the angle. The fall can be calculated as: fall = 1 meter * tan(11 degrees). This gives approximately 0.193 meters, or 19.3 centimeters of fall over 1 meter of horizontal distance.
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To calculate the fall over a distance of 1.8 meters for a 5-degree angle, you can use the formula: fall = distance × sin(angle). In this case, fall = 1.8 meters × sin(5 degrees) ≈ 1.8 × 0.0872 ≈ 0.157 meters, or about 15.7 centimeters.
To calculate the vertical fall over a horizontal distance at a given angle, you can use trigonometry. In this case, the fall at 2 degrees over 6 meters can be calculated using the formula: vertical fall = horizontal distance * tan(angle). Plugging in the values, the vertical fall would be approximately 0.21 meters, or 21 centimeters.
To calculate the fall (or slope) of a 3-degree roof over a distance of 2 meters, you can use the formula: fall = distance × tan(angle). In this case, the fall would be approximately 2 meters × tan(3 degrees), which equals about 0.105 meters, or 10.5 centimeters. Thus, the roof would fall approximately 10.5 cm over the 2-meter span.
Three times the answer to the related question below.
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A fall of 4 degrees over 1 meter refers to a slope or incline where the vertical drop is 4 degrees relative to the horizontal. To calculate the vertical drop, you can use the tangent function: the vertical drop is approximately 0.07 meters (or 7 centimeters) over 1 meter of horizontal distance. This represents a gentle slope, as 4 degrees is a small angle.
A 1-degree fall over a distance of 3 meters corresponds to a vertical drop of approximately 0.052 meters, or 5.2 centimeters. This is calculated using the tangent of the angle (1 degree) multiplied by the distance (3 meters). In practical terms, this means that for every 3 meters of horizontal run, the roof would drop about 5.2 centimeters.
Ah, what a lovely question. When a roof has a 3-degree slope over a 3-meter span, the fall would be 0.155 meters, or about 15.5 centimeters. Just imagine the rain gently trickling down, creating a peaceful rhythm on your roof. Remember, mistakes are just happy little accidents in the world of DIY projects.
To calculate the fall over a 5-degree roof pitch over a 6-meter span, you can use the tangent of the angle. The height (fall) is equal to the length multiplied by the tangent of the angle: ( \text{Fall} = 6 , \text{m} \times \tan(5^\circ) ). This results in approximately 0.52 meters, or 52 centimeters of fall over the 6-meter length.
To calculate the fall (or drop) of an 8-degree roof over a distance of 1 meter, you can use the tangent function from trigonometry. The formula is: fall = distance × tan(angle). For an 8-degree angle, the fall is approximately 1 meter × tan(8°), which equals about 0.14 meters, or 14 centimeters.
A 1 in 80 fall over 4.5 meters indicates a slope where for every 80 units of horizontal distance, there is a vertical drop of 1 unit. To calculate the vertical drop over 4.5 meters (4500 mm), you can use the ratio: (4500 mm / 80) = 56.25 mm. Therefore, over 4.5 meters, the slope would have a vertical drop of approximately 56.25 mm.